SOLUTION: One number is 1 more than twice another. Their product is 1. Find the numbers
Set 1: (lower values)
(smaller value)=
(larger value)=
Set 2: (higher values)
(smaller va
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Set 1: (lower values)
(smaller value)=
(larger value)=
Set 2: (higher values)
(smaller va
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Question 440536: One number is 1 more than twice another. Their product is 1. Find the numbers
Set 1: (lower values)
(smaller value)=
(larger value)=
Set 2: (higher values)
(smaller value)=
(larger value)= Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! x=2y+1
xy=1
y(2y+1)=1
2y^2+y=1
2y^2+y-1=0
2*-1=-2; 2 and -1 are factors of -2 whose sum is 1.
2y^2+2y-y-1=0
2y(y+1)-(y+1)=0
(2y-1)(y+1)=0
y=1/2, y=-1
.
Set 1: (lower values)
(smaller value)=-1
(larger value)=-1
Set 2: (higher values)
(smaller value)=1/2
(larger value)=2
.
Ed