Question 440439: Write an equation that is perpendicular to y=dx-3 that passes through (4d,5) in slope-intercept.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Write an equation that is perpendicular to y=dx-3 that passes through (4d,5) in slope-intercept
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y=dx-3
this is an equation of a straight line of the form: y=mx+b, where m=slope and b=y-intercept
slope of give equation=d
slope of line perpendicular to given line=negative reciprocal of given line=-1/d
finding, b, of perpendicular line:
y=mx+b
5=-1/d(4d)+b
5=4+b
b=1
Equation:
y=-(1/d)x+1 (ans)
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