SOLUTION: find the center of the ellipse: {{{36x^2+64y2-36x-96y-531=0}}}

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Question 440305: find the center of the ellipse: 36x%5E2%2B64y2-36x-96y-531=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

36x%5E2-36x+%2B64y2-96y+=+531

   36(x-1/2)^2 + 64(y-(3/4))^2 = 531 + 9 + 36

   36(x-1/2)^2 + 64(y-(3/4))^2 = 576

   %28x-1%2F2%29%5E2%2F16+%2B+%28y-%283%2F4%29%29%5E2%2F9+=+1+ C(.5,.75)