SOLUTION: how would you solve log base 2(5x-1)- log base 2(x+7)=1

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Question 440270: how would you solve
log base 2(5x-1)- log base 2(x+7)=1
Found 2 solutions by Gogonati, ewatrrr:
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
=log%282%2C+%285x-1%29%29-log%282%2C+%28x%2B7%29%29=log%282%2C+2%29 =>
log%282%2C+%285x-1%29%2F%28x%2B7%29%29=log%282%2C+2%29,
%285x-1%29%2F%28x%2B7%29=2, solve this rational equation. Assume x different from -7,
multiply both sides by x+7 5x-1=2%28x%2B7%29=> 3x=15=> x=5.
Done.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi





  (5x-1)/(x+7) = 2^1

    5x-1 = 2(x+7)

       3x = 15

        x = 5

Familiarize Yourself with the Properties of Logarithms