SOLUTION: Can you help me on this problem? Tennis balls are packaged three to a cylindrical can. If the diameter of a tennis ball is 2 1/2 inches, find the volume of the can.

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Question 439890: Can you help me on this problem?
Tennis balls are packaged three to a cylindrical can. If the diameter of a tennis ball is 2 1/2 inches, find the volume of the can.

Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Tennis balls are packaged three to a cylindrical can. If the diameter of a tennis ball is 2 1/2 inches, find the volume of the can.
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The height of the can is 3*diameter of a ball = 3*(5/2) = 15/2 inches
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Diameter of the base = diameter of a ball = 5/2 inches.
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Volume = Area of base*height
Vol = (pi)*(5/4)^2*(5/2)
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Vol = 3.906(pi) cu. in.
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Vol = 12.2718 cu. in.
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Cheers,
Stan H.
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Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
First, find the volume of a tennis ball.
V+=+4%2Api%2Ar%5E3%2F3
V+=+4%2Api%2A%282.5%2F2%29%5E3%2F3
V+=8.2in%5E3
If 3 are packed into a cylinder, like the cans tennis balls are sold in, the volume would be 3 times the volume of a ball,
V+=3%2A8.2in%5E3=24.5in%5E3... that's the volume of the 3 balls....
To put them into a cylinder, the cylinder would have in inside diameter of 2.5 inches (or radius 1.2in), and it would be 3 times the diameter of a ball, or 7.5 inches.
For a cylinder,
V+=+pi%2Ar%5E2%2Ah
V+=+pi%2A1.25%5E2%2A7.5
V+=36.8in%5E3