SOLUTION: sqrt(x-3) + sqrt (x+5) = 4 Isolating one radical (sqrt x-3)^2 = (4 - sqrt(x+5))^2 Using the principle of powers - squaring both sides x - 3 = 16 - 8 (sqrt (x+5)) + (x+5) What I

Algebra ->  Radicals -> SOLUTION: sqrt(x-3) + sqrt (x+5) = 4 Isolating one radical (sqrt x-3)^2 = (4 - sqrt(x+5))^2 Using the principle of powers - squaring both sides x - 3 = 16 - 8 (sqrt (x+5)) + (x+5) What I      Log On


   



Question 439831: sqrt(x-3) + sqrt (x+5) = 4 Isolating one radical
(sqrt x-3)^2 = (4 - sqrt(x+5))^2 Using the principle of powers - squaring both sides
x - 3 = 16 - 8 (sqrt (x+5)) + (x+5)
What I would like to know is where does the 8 come from?

Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
Remember from algebra the formula: %28a-b%29%5E2=a%5E2+-2ab%2Bb%5E2 in our case: