Question 439815: Please help find the solution to the equation, correct to two decimal places
Log base 2 (x+2) + log base 2 (x-1) = 2 Answer by ewatrrr(24785) (Show Source):
Hi
(x+2)(x-1) = 2^2
x^2+x-2= 4
x^2 + x -6 = 0
factoring
(x+3)(x-2) = 0
(x+3)= 0
x = -3 Extraneous Solution |results in
x = 2
Familiarize yourself with the Properties of Logarithms