SOLUTION: Hooke's Law states that the distance a spring stretches varies directly as the weight on the spring increases. A weight of 80 lbs. stretches a spring 4.5 inches. How far (to the
Question 43970: Hooke's Law states that the distance a spring stretches varies directly as the weight on the spring increases. A weight of 80 lbs. stretches a spring 4.5 inches. How far (to the nearest 0.01 inch) will a weight of 125 pounds stretch the spring? Answer by adamchapman(301) (Show Source):
You can put this solution on YOUR website! The equation governing the extension of a spring is
where k is the stiffness (force per unit length) and F is the force applied. x is the extension of the spring.
A weight of 80 pounds stretches a spring 4.5 inches. So rearranging the equation given,
Now when 125 pounds are applied:
Rearranging:
the solution is x=7.03 inches (to the nearest 0.01 inch)
I hope this helps.
P.S. I am trying to start my own mathematics homework help website. I would be extremely grateful if you would send me your feedback on my help to adam.chapman@student.manchester.ac.uk.