Question 439599: $9500 is invested, part of it at 10% and part of it at 6%. for a certain year, the total yield is $806.00. how much was invested? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! x+y=9500
.1x+.06y=806
Multiply the second equation by 100:
10x+6y=80600
6x+6y=57000
4x=23600
x=5900
y=3600
$5900 was invested at 10%, $3600 was invested at 6%..