SOLUTION: hello. i need help with these few problems. {{{ log ( 2, 25 ) }}} and {{{ log ( 2, 3/5 ) }}} and {{{ log ( 2, 15 ) }}} and {{{ log ( 2, 75 ) }}} i just dont know how to approach th
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-> SOLUTION: hello. i need help with these few problems. {{{ log ( 2, 25 ) }}} and {{{ log ( 2, 3/5 ) }}} and {{{ log ( 2, 15 ) }}} and {{{ log ( 2, 75 ) }}} i just dont know how to approach th
Log On
You can put this solution on YOUR website! log ( 2, 25 ) }}} and and and
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There is a Law of Logs called the change of base law.
It says: loga(b) = logc(b)/logc(a)
where c is any base you care to use.
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Your problem:
log2(25) = log(25)/log(2) = 1.3979/0.3010 = 4.644
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Using your calculator:
log2(3/5) = log(3/5)/log(2) = -0.7370
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log2(75) = log(75)/log(2) = 6.2288
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Cheers,
Stan H.
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