SOLUTION: graph the equation, then choose the correct coordinates of the foci. y^2 = 5x^2 + 25

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: graph the equation, then choose the correct coordinates of the foci. y^2 = 5x^2 + 25      Log On


   

Question 43949: graph the equation, then choose the correct coordinates of the foci.
y^2 = 5x^2 + 25
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E2+=+5x%5E2+%2B+25
y%5E2+-+5x%5E2+=+25
%28y%5E2%29%2F25+-+%28x%5E2%29%2F5+=+1
Center: (0,0)
Transverse Axis: vertical
a = 5
b = sqrt%285%29
c%5E2+=+a%5E2+%2B+b%5E2
c+=+sqrt%2825+%2B+5%29
c+=+sqrt%2830%29
Vertex: (0,5) and (0,-5)
Foci: (0,sqrt%2830%29) and (0,-sqrt%2830%29)