SOLUTION: IF the sum of the measures of the interior angles of a polygon is twice the sum of its exterior angles, how many sides does it have?

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Question 439488: IF the sum of the measures of the interior angles of a polygon is twice the sum of its exterior angles, how many sides does it have?
Answer by Gogonati(855) About Me  (Show Source):
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As you know the sum of exterior angels in each polygon is 360 degree.
Let n the number of angels in our polygon then the sum of interior angels is:
%28n-2%29%2A180, since this sum is twice the sum of exterior angels we write:
%28n-2%29180=2%2A360 => n-2=%282%2A360%29%2F180 => n-2=4 => n=6.
Answer:On the hexagon the sum of interior angels is twice of the sum of its exterior angels.