SOLUTION: in triangle abc angle A=53, angle B=14, and a=10. Find b to the nearest integer.

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Question 439407: in triangle abc angle A=53, angle B=14, and a=10. Find b to the nearest integer.
Found 2 solutions by stanbon, robertb:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
in triangle abc angle A=53, angle B=14, and a=10. Find b to the nearest integer.
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Use Law of Sines:
b/sin(14) = 10/sin(53)
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b = [sin(14)/sin(53)]10
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b = 3.0292
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Cheers,
Stan H.
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Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Use the Sine Law: b+=+a%28sinB%2FsinA%29+=+10%28sin14%29%2F%28sin53%29+=+3.03 but b = 3 to the nearest integer.