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Question 439372: Can I get help with the following problem please!!
Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b form)
Found 3 solutions by stanbon, robertb, Alan3354:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Can I get help with the following problem please!!
Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b form)
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f'(x) = [(3x-2)(4)-(4x+1)/(3)]/(3x-2)^2
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f' = [(12x-8)-(4x+1)]/(3x-2)^2
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f' = [8x-9]/[3x-2]^2
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f'(1,-2) = [8-9]/[3-2]^2 = 1/1 = 1
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Form: y = mx + b
-2 = 1*1 + b
b = -3
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Equation of the tangent line at (1,-2):
y = x-3
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Cheers,
Stan H.
Answer by robertb(5830)  (Show Source):
You can put this solution on YOUR website! 
At (1, -2),  , the slope of the tangent line.
==> Equation of the tangent line is y--2 = -11(x-1), or
y+2 = -11x + 11, or y = -11x + 9.
Answer by Alan3354(69443)  (Show Source):
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