SOLUTION: Find all values of θ in the interval 0 ≤ θ < 360° that satisfy the equation 2 sin^2 θ + sin θ = 1
Thanks
Kamla
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-> SOLUTION: Find all values of θ in the interval 0 ≤ θ < 360° that satisfy the equation 2 sin^2 θ + sin θ = 1
Thanks
Kamla
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Question 439348: Find all values of θ in the interval 0 ≤ θ < 360° that satisfy the equation 2 sin^2 θ + sin θ = 1
Thanks
Kamla Found 2 solutions by stanbon, robertb:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find all values of θ in the interval 0 ≤ θ < 360° that satisfy the equation 2 sin^2 θ + sin θ = 1
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sin^2 + sin -1 = 0
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Use the Quadratic Formula:
theta = [-1 +- sqrt(1-4*1*-1)]/2
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theta = [-1 +- sqrt(5)]/2
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theta = [-1+sqrt(5)]/2 or theta = [-1-sqrt(5)]/2
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Cheers,
Stan H.
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