SOLUTION: IN A PEN OF GOATS AND CHICKENS, THERE ARE 40 HEADS AND 130 FEET. HOW MANY GOATS AND CHICKENS ARE IN THE PEN??

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Question 439278: IN A PEN OF GOATS AND CHICKENS, THERE ARE 40 HEADS AND 130 FEET. HOW MANY GOATS AND CHICKENS ARE IN THE PEN??
Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let's GOATS be x
and
CHICKENS be y
given:
there are 40 HEADS....-> 40=x%2By .........1
130 FEET....-> 130+=4x%2B2y................2
40=x%2By+.........1
130+=4x%2B2y......2
---------------------solve the system
40=x%2By ....-> x=40-y.......substitute in 2
130+=4%2840-y%29%2B2y
130+=+160-4y%2B2y
130-160+=-y
-30+=-2y
2y=30
y=15.............CHICKENS
x=40-15
x=25.............GOATS


Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
IN A PEN OF GOATS AND CHICKENS, THERE ARE 40 HEADS AND 130 FEET. HOW MANY GOATS AND CHICKENS ARE IN THE PEN??
All animals have a pair of front feet. 130 feet is 130÷2 or 65 
pairs of feet.  There are 40 pairs of front feet.  So 
the remaining 65-40 or 25 pairs of feet are hind feet and belong 
to the goats, so there are 25 goats and 40-25 or 15 chickens.


By algebra,

 G +  C = 40
4G + 2C = 130

Solve that and get G=25 and C=15

Edwin