Question 43902: By using the Factor Theorem, Find the Prime factors of the polynomial:
x^3 - x^2 - 17x - 15
Found 2 solutions by fractalier, Nate:
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! x^3 - x^2 - 17x - 15
has rational factors ±1, ±3, ±5, or ±15
Since 1 does not work, we try -1...and it works...so does -3 and 5 so that it factors into
(x + 1)(x + 3)(x - 5)
Answer by Nate(3500)  (Show Source):
You can put this solution on YOUR website! x^3 - x^2 - 17x - 15
a = factors of constant = 1,3,5,15
b = factors of leading coefficient = 1
Possible Answers: +- a/b = +- 1,3,5,15
Pos: 1 .. 1
Neg: 2 .. 0
Imag:0 .. 2
(x + 1)(x + 3)(x - 5)
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