SOLUTION: how would you factor 121x^2+198x-29

Algebra ->  Rational-functions -> SOLUTION: how would you factor 121x^2+198x-29      Log On


   

Question 438943: how would you factor 121x^2+198x-29
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
121x² + 198x - 29 is prime, that is, it cannot be factored
using integers.

However if it was supposed to be

121x² + 198x - 19 and you accidentally mistyped a 2 for a 1,
it would factor as

(11x + 19)(11x - 1)

Edwin