SOLUTION: The area of a certain square is 5 more than its perimiter. What is the length of each side of the square---thanks in advance

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Question 438904: The area of a certain square is 5 more than its perimiter. What is the length of each side of the square---thanks in advance
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
x2-5=4x
x2-4x-5=0
(x+1)(x-5)=0
x=-1 or 5.
Throwing away the negative answer, we get the side of the square to be 5.