SOLUTION: find the solution to the equation: x^2+2x+5=0 a.x= -1 + - 2i b.x= 1 + - 2i c.x= -2 + - 4i d.x= 2 + - 4i using the solver it said there were no solutions, and i am confus

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: find the solution to the equation: x^2+2x+5=0 a.x= -1 + - 2i b.x= 1 + - 2i c.x= -2 + - 4i d.x= 2 + - 4i using the solver it said there were no solutions, and i am confus      Log On


   

Question 43889: find the solution to the equation: x^2+2x+5=0
a.x= -1 + - 2i
b.x= 1 + - 2i
c.x= -2 + - 4i
d.x= 2 + - 4i
using the solver it said there were no solutions, and i am confused on how to
answer,
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
x%5E2%2B2x%2B5+=+0 This will not factor so use the quadratic formula:
x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a where, from your equation:
a = 1, b = 2, c = 5
x+=+%28-2%2B-sqrt%282%5E2-4%281%29%285%29%29%29%2F2%281%29
x+=+%28-2%2B-sqrt%284-20%29%29%2F2
x+=+%28-2%2B-sqrt%28-16%29%29%2F2
x+=+-1%2B2i or x+=+-1-2i
As you can see, there are solutions to the equation but they are not real solutions, they are complex solutions.