SOLUTION: A vendor sells hot dogs and bags of potato chips. A customer buys 3 hot dogs and 2 bags of potato chips for $8.25. Another customer buys 4 hot dogs and 4 bags of potato chips for $

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A vendor sells hot dogs and bags of potato chips. A customer buys 3 hot dogs and 2 bags of potato chips for $8.25. Another customer buys 4 hot dogs and 4 bags of potato chips for $      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 438828: A vendor sells hot dogs and bags of potato chips. A customer buys 3 hot dogs and 2 bags of potato chips for $8.25. Another customer buys 4 hot dogs and 4 bags of potato chips for $13.00. Find the cost of each item.

also what equations would i use?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A vendor sells hot dogs and bags of potato chips. A customer buys 3 hot dogs and 2 bags of potato chips for $8.25. Another customer buys 4 hot dogs and 4 bags of potato chips for $13.00. Find the cost of each item.
------------------------------------
3d + 2p = 825 cents
4d + 4p = 1300
------
Multiply thru 1st equation by 2:
----
6d + 4p = 2*825
4d + 4p = 1300
------
Subtract and solve for "d":
2d = 350
d = $1.75 (price of one hot dog)
----
Solve for "p":
3d + 2p = 825
3(175)+2p = 825
2p = 300
p = $1.50 (price of one bag of potato chips.
------------------
Cheers,
Stan H.
==================