SOLUTION: the product of 3 consecutive integers is 3 more than 3 times the second integer. Find the 3 integers

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Question 438795: the product of 3 consecutive integers is 3 more than 3 times the second integer. Find the 3 integers
Answer by rwm(914) About Me  (Show Source):
You can put this solution on YOUR website!
x*(x+1)*(x+2)=3(x+1)+3
3x+3+3=3x+6=3(x+2)
x*(x+1)*(x+2)=3(x+2)
x^3+3x^2+2x = 3x+6
x^3+3x^2-x-6 = 0
x=-2 and other non integers
-2, -1, 0
check
-2*-1*0=0
-3+3=0
ok