SOLUTION: Prove that in an acute angled triangle ABC , a/sin A = b/sin B =c/sin C

Algebra ->  Trigonometry-basics -> SOLUTION: Prove that in an acute angled triangle ABC , a/sin A = b/sin B =c/sin C      Log On


   

Question 438759: Prove that in an acute angled triangle ABC , a/sin A = b/sin B =c/sin C
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
That formula is true not only for "acute angled " triangles, but for all triangles in the plane. It's called the Sine Law. Read any standard trigonometry textbook for a proof, or go to Wikipedia or somewhere.