SOLUTION: The sum of three integers is two hundred eighty. The second number is ten less than twice the first number. The third number is four times the second number. Find the three numbers
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Question 438348: The sum of three integers is two hundred eighty. The second number is ten less than twice the first number. The third number is four times the second number. Find the three numbers? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Write an equation for each statement:
:
The sum of three integers is two hundred eighty.
x + y + z = 280
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The second number is ten less than twice the first number.
y = (2x-10)
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The third number is four times the second number.
z = 4y
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We will do it in terms of x, replace y in the above equation with (2x-10)
z = 4(2x-10)
z = (8x-40)
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Replace y and z in the sum equation
x + (2x-10) + (8x-40) = 280
11x - 50 = 280
11x = 280 + 50
11x = 330
x =
x = 30
:
I'll let you find y and z, check your solutions in the sum equation
