SOLUTION: the length of a room is 5 feet more than the width of the room. the perimeter of the room id 70 feet. find the length and width of the room.

Algebra ->  Rectangles -> SOLUTION: the length of a room is 5 feet more than the width of the room. the perimeter of the room id 70 feet. find the length and width of the room.      Log On


   



Question 4383: the length of a room is 5 feet more than the width of the room. the perimeter of the room id 70 feet. find the length and width of the room.
Answer by arunpaul(104) About Me  (Show Source):
You can put this solution on YOUR website!
let length of room = l
width of the room = w
as per the question l = w + 5'
the perimeter of room = 70'
or 2(l+w) = 70
putting the value of l in the above equation we have
2(w+5+w) =70
or 2w +5 = 70/2
or 2w = 35 - 5
or 2w = 30
or w = 30/2
or w = 15'
so putting the value of w in l
we have length of room = l = w + 5 = 15 + 5 = 20
so length = l = 20 feet
width = w = 15 feet (Ans)