SOLUTION: The polynomial f(x)divided x-3 results in a quotient of x^2+3x-5 with a remainder of 2. Find f(3). my answer is -2, could that be right. thanks again.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The polynomial f(x)divided x-3 results in a quotient of x^2+3x-5 with a remainder of 2. Find f(3). my answer is -2, could that be right. thanks again.      Log On


   

Question 43813This question is from textbook Algebra and trigonometry with analytic geometry
: The polynomial f(x)divided x-3 results in a quotient of x^2+3x-5 with a remainder of 2. Find f(3). my answer is -2, could that be right. thanks again. This question is from textbook Algebra and trigonometry with analytic geometry

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
To find the original f(x) we need to multiply
(x^2 + 3x - 5) by (x - 3) and then adding 2...we get
f(x) = x^3 - 14x + 15 + 2
f(x) = x^3 - 14x + 17
so that
f(3) = 3^3 - 14(3) + 17
f(3) = 27 - 42 + 17
f(3) = 2
Close, but I get positive 2, not -2.