SOLUTION: I am trying to do logarithmic equations and is having a difficult time finding a solution. Please help.
The problems are:
Problem #1: log(base3)x = 2 log(base3)3 + log
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: I am trying to do logarithmic equations and is having a difficult time finding a solution. Please help.
The problems are:
Problem #1: log(base3)x = 2 log(base3)3 + log
Log On
Question 438096: I am trying to do logarithmic equations and is having a difficult time finding a solution. Please help.
The problems are:
Problem #1: log(base3)x = 2 log(base3)3 + log (base3)5
Problem #2: log(base5)(x^2-9) = 4 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Problem #1: log(base3)x = 2 log(base3)3 + log (base3)5
Problem #2: log(base5)(x^2-9) = 4
..
Problem #1
log(base3)x = 2 log(base3)3 + log (base3)5
log of its base=1
log3(3)=1
log3(x)=2(1)+log3(5)
log3(x)-log3(5)=2
log3(x/5)=2
convert to exponential form (base raised to log of number=number)
3^2=x/5
9=x/5
x=45
..
Problem#2
log5(x^2-9) = 4
convert to exponential form
5^4=x^2-9
625=x^2-9
x^2=625-9=616
x=+-sqrt(616)=+-24.82
(