SOLUTION: last one.... if there are 5 different stat books, 3 dif prob books and 3 dif exam prep books, how many ways can they be arranged if all the books 0f the same type remain next to ea
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-> SOLUTION: last one.... if there are 5 different stat books, 3 dif prob books and 3 dif exam prep books, how many ways can they be arranged if all the books 0f the same type remain next to ea
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Question 437759: last one.... if there are 5 different stat books, 3 dif prob books and 3 dif exam prep books, how many ways can they be arranged if all the books 0f the same type remain next to each other??? Once again...I know it is a permutation but how can I show how to solve the problem rather than plugging the 3's into my calculator?
Thanks Much! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! if there are 5 different stat books, 3 dif prob books and 3 dif exam prep books, how many ways can they be arranged if all the books 0f the same type remain next to each other???
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Arrange the 3 types of book: 3! = 6 ways
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Arrange the books in each of the 3 types: 3!*3!*3! = 6^3 =
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Ans: 6^4 = 1296
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Cheers,
Stan H.
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