SOLUTION: What are the solutions to, x^2-2x=0.

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Question 43741: What are the solutions to, x^2-2x=0.
Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
In order to solve this quadratic equation, we must use the quadratic formula:
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-2x%2B0+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-2%29%5E2-4%2A1%2A0=4.

Discriminant d=4 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--2%2B-sqrt%28+4+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-2%29%2Bsqrt%28+4+%29%29%2F2%5C1+=+2
x%5B2%5D+=+%28-%28-2%29-sqrt%28+4+%29%29%2F2%5C1+=+0

Quadratic expression 1x%5E2%2B-2x%2B0 can be factored:
1x%5E2%2B-2x%2B0+=+%28x-2%29%2A%28x-0%29
Again, the answer is: 2, 0. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-2%2Ax%2B0+%29



Therefore, we've found that the two solutions to this equation are x = 2 and x = 0.

I hope this helps!
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