Question 437392: 7^(2x+1)=1/3^(2-x)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! 7^(2x+1)=1/3^(2-x)
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7^(2x+1)=1/3^(2-x)
(2x+1)log7=(2-x)log1/3
(2x+1)log7=(2-x)(log1-log3)
log1=0
(2x+1)log7=(2-x)(-log3)
2xlog7+log7=-2log3+xlog3
2xlog7-xlog3=-2log3-log7
x(2log7-log3)=-2log3-log7
x=(-2log3-log7)/(2log7-log3)
use calculator from here
x=(-1.79934)/1.21307
x=-1.48329
Check:
7^(2x+1)=7^-1.96658=.02178
1/3^(2-x)=1/3^3.48329=.02178
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