SOLUTION: The general expression for consecutive multiples of 6 is 6N, 6(N+1), 6(N+2), etc. Find three consecutive multiples of 6 such that 4 times the first exeeds twice the third by 12.

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Question 437357: The general expression for consecutive multiples of 6 is 6N, 6(N+1), 6(N+2), etc. Find three consecutive multiples of 6 such that 4 times the first exeeds twice the third by 12.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
4x6n=2x6(n+2)+12
24n=12n+24+12
24n=12n+36
12n=36
n=3
6n=18
6(n+1)=24
6(n+2)=30.