SOLUTION: i need help with this problem. 4x^3+4x^2-29x+21 divided by 2x-3

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Question 437318: i need help with this problem.
4x^3+4x^2-29x+21 divided by 2x-3
Found 2 solutions by shree840, rwm:
Answer by shree840(260) (Show Source):
You can put this solution on YOUR website!
4x^3+4x^2-29x+21
--------------------
2x-3

2x-3!-------------------- 2x^2+5x-7
4x^3+4x^2-29x+21
4x^3 -6x^2
------------------------------
10x^2-29x+21
10x^2-15x
-----------------
-14x+21
-14x +21
---------
0
Ans 2x^2+5x-7

Answer by rwm(914) (Show Source):
You can put this solution on YOUR website!
4x^3+4x^2-29x+21=(x-1)*(2x+7)*(2x-3)
so we get
(x-1)*(2 x+7)
or
2x^2+5x-7
here are the steps
2x-3 into 4x^3+4x^2-29x+21
first quotient is 2x^2
then 5x
4x^2-15x
then -7
-14x+21
with zero remainder