SOLUTION: solve with substitutions: -2 x + 1 y = 10 .............1 1 y = -6 -2 x ---------2 / 1 = y = -6 + -2 x Plug the value of y in (1) -2 x + 1 (

Algebra ->  Systems-of-equations -> SOLUTION: solve with substitutions: -2 x + 1 y = 10 .............1 1 y = -6 -2 x ---------2 / 1 = y = -6 + -2 x Plug the value of y in (1) -2 x + 1 (      Log On


   

Question 437188: solve with substitutions:
-2 x + 1 y = 10 .............1
1 y = -6 -2 x ---------2
/ 1 =
y = -6 + -2 x
Plug the value of y in (1)
-2 x + 1 ( -6 + -2 x ) = 10
-2 x + -6 + -2 x = 10
-2 x + -2 x = 10 6
-4 x = 16
/ -4
x= -4
Plug the value of x in (1)
-2 x + 1 y = 10
-2 * -4 + 1 y = 10
8 + 1 y = 10
1 y = 2
/ 1
y= 2

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
-2x+y=10 .............1
y=-6-2x ---------2
Plug the value of y in (1)
-2x+(-6-2x)= 10
-2x-6-2 x=10
-2x-2x=10+6
-4x=16
/-4
x=-4
Plug the value of x in (1)
-2x+y=10
-2*-4+ y=10
8+y=10
y=2