SOLUTION: when one integer is added to the square of the next consecutive integer, the sum is 71.Find the two integers.

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Question 437167: when one integer is added to the square of the next consecutive integer, the sum is 71.Find the two integers.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
x+(x+1)2=71
x+x2+2x+1=71
x2+3x-70=0
(x+10)(x-7)=0
x=-10,7
Ignoring the negative result, we get the first integer to be 7, the second to be 8.