SOLUTION: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13. and Find an equation of the line containing the point (-2,-5) and perpendicular

Algebra ->  Linear-equations -> SOLUTION: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13. and Find an equation of the line containing the point (-2,-5) and perpendicular       Log On


   

Question 437070: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13.
and
Find an equation of the line containing the point (-2,-5) and perpendicular to the line 4x-5y=13.
For the first question I got y=(4/5)x-17/5 is this right and how do you do the other one.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the first one is right

perpendicular lines have slopes which are negative reciprocals of each other
___ so you can just swap the x and y coefficients and change one of the signs

5x + 4y = ? ___ to find ? , just plug in the necessary point

5(-2) + 4(-5) = -30

5x + 4y = -30