SOLUTION: Solve for x Log of 2 2^x-5=5 I have x=7.32 Lne^-2x=-10 I have X=1.61 3^x = 30 I have 3.096 Use change of base formula and a clculator to approximate each logarith

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve for x Log of 2 2^x-5=5 I have x=7.32 Lne^-2x=-10 I have X=1.61 3^x = 30 I have 3.096 Use change of base formula and a clculator to approximate each logarith      Log On


   



Question 43697: Solve for x
Log of 2 2^x-5=5 I have x=7.32
Lne^-2x=-10 I have X=1.61
3^x = 30 I have 3.096 Use change of base formula and a clculator to approximate each logarithm to 3 decimal places.
Log of 5 1.256 I have =0.142
Log(-7)= can't take lof of a negative number.
Please help.

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2C2%5E%28x-5%29%29+=+5
x+-+5+=+5
x+=+10
log%28e%2Ce%5E%28-2x%29%29+=+-10
-2x+=+-10
x+=+5
3%5Ex+=+30
log%2810%2C3%5Ex%29+=+log%2810%2C30%29
x%2Alog%2810%2C3%29+=+log%2810%2C30%29
x+=+log%2810%2C30%29%2Flog%2810%2C3%29 About 3.096
log%285%2C1.256%29+=+x
1.256+=+5%5Ex
log%2810%2C1.256%29+=+log%2810%2C5%5Ex%29
log%2810%2C1.256%29+=+x%2Alog%2810%2C5%29
log%2810%2C1.256%29%2Flog%2810%2C5%29+=+x About 0.142
log%2810%2C-7%29+=+x
-7+=+10%5Ex Ten to any power will not equal a negative number. The closest you can get to a negative number is by x+=+-infinity, but the result is only a small fraction that is positive.