SOLUTION: Find the center of a circle with equation: x^2 + y^2 - 6x + 4y - 4 = 0

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Question 436864: Find the center of a circle with equation: x^2 + y^2 - 6x + 4y - 4 = 0
Answer by Alan3354(69443) About Me  (Show Source):
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Find the center of a circle with equation: x^2 + y^2 - 6x + 4y - 4 = 0
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Complete the squares to make it standard form,
%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 where (h,k) is the center
x%5E2+%2B+y%5E2+-+6x+%2B+4y+=+4

(x-3)^2 + (y+2)^2 = 17
Center at (3,-2)