Question 436850: Coordinate-system/436845
Let H(x)= 2x^3 + 5x - 2
Find H^(-1) (-2).
trying to understand your method of distribution
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==> Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Let H(x)= 2x^3 + 5x - 2
Find H^(-1) (-2).
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The exponent symbol ^ doesn't make sense there.
If you want H(-1) and H(-2)
Let H(x)= 2x^3 + 5x - 2
Find H(-1)
Sub -1 for x
H(-1) = 2(-1)^3 + 5(-1) - 2 = -2 -5 -2
H(-1) = -9
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H(-2) = 2(-2)^3 + 5(-2) - 2 = -16 -10 -2
H(-2) = -28