SOLUTION: How do you find the axis of symmetry of the equation.... y=-3x^2-6x+4 ?

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Question 43683: How do you find the axis of symmetry of the equation.... y=-3x^2-6x+4 ?
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+-3x%5E2+-+6x+%2B+4
Since this is a vertical parabola, you would use the x value of the vertex.
V((-b/2a),f(x)) = V((-1),f(x))
Axis of Symmetry: x+=+-1
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-3x%5E2+-+6x+%2B+4+%29+