SOLUTION: The sum of the squares of two consecutive odd positive integers is 202. Find the numbers

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The sum of the squares of two consecutive odd positive integers is 202. Find the numbers      Log On


   

Question 436647: The sum of the squares of two consecutive odd positive integers is 202. Find the numbers
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+%28x+%2B+2%29%5E2+=+202
x%5E2+%2B+x%5E2+%2B+4x+%2B+4=+202
2x%5E2+%2B+4x+-198+=+0
x%5E2+%2B+2x+-+99=+0
<==> (x +11)(x - 9) = 0 ==> x = 9 ==> x +2 = 11.
(Don't accept x = -11. Why?)