SOLUTION: am stuck with this question on proving in geometry.
Given a triangle ABC prove that
{{{cot(C) = expr(a/c)cosec(B)- cot(B)}}}
the substitution has been slightly tricky
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Given a triangle ABC prove that
{{{cot(C) = expr(a/c)cosec(B)- cot(B)}}}
the substitution has been slightly tricky
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Question 436542: am stuck with this question on proving in geometry.
Given a triangle ABC prove that
the substitution has been slightly tricky Answer by Edwin McCravy(20064) (Show Source):
You can put this solution on YOUR website! am stuck with this question on proving in geometry.
Given a triangle ABC prove that
the substitution has been slightly tricky
Next draw an altitude (perpendicular) from A to BC,
and label it h.
That green altitude divides the base BC of length "a"
into two parts, we'll let "x" represent the right part
of "a", and the left part will be "a-x"
Using the right triangle on the right:
Using the right triangle on the left:
Substituting into
Cancel the c's in the first term on the right:
The fractions on the right have a common denominator so
we can combine the numerators:
Edwin