SOLUTION: Oil tanker A leaves Corpus Christi, Texas heading due east toward St. Petersburg, Florida at a speed of 15 mph. At the same time, tanker B leaves St. Petersburg, Florida heading du
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-> SOLUTION: Oil tanker A leaves Corpus Christi, Texas heading due east toward St. Petersburg, Florida at a speed of 15 mph. At the same time, tanker B leaves St. Petersburg, Florida heading du
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Question 436414: Oil tanker A leaves Corpus Christi, Texas heading due east toward St. Petersburg, Florida at a speed of 15 mph. At the same time, tanker B leaves St. Petersburg, Florida heading due west toward Corpus Christi, Texas at a speed of 29 mph. The distance between the two ports is 900 miles.
A. How far are the tankers from Corpus Christi when they meet?
B. Write a compound inequality for the time interval during which they are within 110 miles of eachother.
(round all answers to the nearest hundredth) Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Tanker A due East 15 km/h
Tanker B due West 29 km/h
Distance 900 miles
Let time they meet be x hours
Tanker A due East distance traveled 15 x miles
Tanker B due West distance traveled 16 x miles
Time taken to meet is same
t=d/r
combined speed= 44 mph
44 x = 900
x= 20.45 hours
Tanker A due East 15x=306.82 miles from Corpus Christi
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