SOLUTION: It has been 60 years since I had math using Log functions. I would like to know how to solve this equation. Thank you for your time and help.
Gordon
Log^-1*(.5)=X
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-> SOLUTION: It has been 60 years since I had math using Log functions. I would like to know how to solve this equation. Thank you for your time and help.
Gordon
Log^-1*(.5)=X
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Question 436343: It has been 60 years since I had math using Log functions. I would like to know how to solve this equation. Thank you for your time and help.
Gordon
Log^-1*(.5)=X Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! It has been 60 years since I had math using Log functions. I would like to know how to solve this equation. Thank you for your time and help.
Gordon
Log^-1*(.5)=X
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It's not clear what you mean.
There's a multiply symbol after the inverse log.
