SOLUTION: 5(h-1)-1=2(h-3)+3h
my solution is 5h-6=5h-6...would this be considered "all real numbers" or h=0? Or possibly something else.Thank you for your help!
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Real-numbers
-> SOLUTION: 5(h-1)-1=2(h-3)+3h
my solution is 5h-6=5h-6...would this be considered "all real numbers" or h=0? Or possibly something else.Thank you for your help!
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Question 436312: 5(h-1)-1=2(h-3)+3h
my solution is 5h-6=5h-6...would this be considered "all real numbers" or h=0? Or possibly something else.Thank you for your help! Answer by richard1234(7193) (Show Source):
