SOLUTION: the parabola which is the graph of the function f: y= ax^2+bx+c, b>0,c<0 does not have any common point with the x-axis the top of this parabola lies in the same quadrant as the po
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Question 436189: the parabola which is the graph of the function f: y= ax^2+bx+c, b>0,c<0 does not have any common point with the x-axis the top of this parabola lies in the same quadrant as the point with the coordinates A. {-1,-1} B.{-3,2} C.{2,-2} D. {1,1} AND PROVE THE ANSWER Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! Since , then , so the entire parabola must be contained within the third and fourth quadrants. Hence, .
The vertex of the parabola occurs at . Since b is positive and a is negative, will be positive. The vertex has a positive x-coordinate and a negative y-coordinate, so it lies in the fourth quadrant, and choice C is correct.
