SOLUTION: Hi ther, I have no idea what im doing,...can you help please? QUESTION: Phan is painting his bed room,Which is 12ft by 14ft.The walls are 9ft high.On one of the longer walls,the

Algebra ->  Surface-area -> SOLUTION: Hi ther, I have no idea what im doing,...can you help please? QUESTION: Phan is painting his bed room,Which is 12ft by 14ft.The walls are 9ft high.On one of the longer walls,the      Log On


   

Question 436039: Hi ther, I have no idea what im doing,...can you help please?
QUESTION:
Phan is painting his bed room,Which is 12ft by 14ft.The walls are 9ft high.On one of the longer walls,there is a a rectangular window that is 9ft by 2ft.One of the shorter walls has a door that is 6.5ft by 3ft.One can of paint covers about 400%5E2. If he puts one coat on each wall,how many cans of paint will phan need?
.....as you can see..if i knew what to do,I wouldnt be here -_-. Thanks Tutors!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There are 4 walls to paint. The dimension that is common to
all 4 walls is the height, 9 ft.
wall #1:
14%2A9+=+126 ft2
wall #2:
+12%2A9+=+108 ft2
wall #3:
+14%2A9+-+9%2A2+=+126+-+18
+126+-+18+=+108 ft2
wall #4:
+12%2A9+-+3%2A6.5+=+108+-+19.5
+108+-+19.5+=+88.5 ft2
The total area of the walls is:
+126+%2B+2%2A108+%2B+88.5+=+430.5 ft2
430.5+-+400+=+30.5
He will need 2 cans,