Question 435976: a man invested 10000$,part at 5 percent and part at 9 percent.if the total yearly interest was 600$, how much did he invest at each rate? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! x+y=10000
.05x+.09y=600
Multiply the second equation by 100
5x+9y=60000
5x+5y=50000
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4y=10000
y=2500
x=7500
He invested $7500 at 5% and $2500 at 9%.