SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

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Question 43588This question is from textbook 0-07-301602-0
: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs. This question is from textbook 0-07-301602-0

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
The leg that is not equal to any other: l
The length of one of the equal legs: 4l - 8
l + (4l - 8) + (4l - 8) = 29
l + 4l + 4l - 8 - 8 = 29
9l - 16 = 29
9l = 45
l = 5
The length of one of the equal legs: 4l - 8 = 20 - 8 = 12