SOLUTION: Graph y> or = √(3x+12).

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Question 43586: Graph y> or = √(3x+12).
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
y+%3E=+sqrt%283x+%2B+12%29
*sorry, the graph doesn't extend all the way to (-4,0)
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%283x+%2B+12%29+%29+
Limitation To Domain:
A real number squared will not give you a negative number, so:
3x+%2B+12+%3E=+0
3x+%3E=+-12
x+%3E=+-4
Vertex: (-4,f(x)) = (-4,0)
Shading:
If you pick the point: (-4,1)
You get: 1+%3E+0 which is correct
You would shade only above the solid line, not to the left or under it.
If it helps you, you can draw a vertical line at x+=+4. Shade above the graphed square root line and to the right of the vertical line.