Question 435792: A person buys 20 tickets. some cost $8 and some cost $5. he spend $118.
How many of each ticket does he buy? Found 3 solutions by stanbon, htmentor, Gogonati:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A person buys 20 tickets. some cost $8 and some cost $5. he spend $118.
How many of each ticket does he buy?
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Quantity Equation: e + f = 20 tickets
Value Equation::: 8e +5f = 118 dollars
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Multiply thru the Quantity Eq. by 8:
8e + 8f = 8*20
8e + 5f = 118
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Subtract and solve for "f":
3f = 42
f = 14 (# of $5 tickets bought)
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Solve for "e":
e + f = 20
e + 14 = 20
e = 6 (# of $8 tickets bought)
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Cheers,
Stan H.
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You can put this solution on YOUR website! Let x = the number of $5 tickets
Then 20-x = the number of $8 tickets
Since the total amount spent is $118, we can write:
5x + 8(20-x) = 118
Collect terms, solve for x:
-3x + 160 = 118 -> 3x = 42 -> x = 14
So the number of $5 tickets is 14, the number of $8 tickets is 6.
You can put this solution on YOUR website! Let x the number of tickets $8, then 20-x is the number of tickets $5. Since he spend $118, we have the below equation:
8x+5(20-x)=118 =>8x-5x=118-100 => 3x=18 => x=6.
Answer:This person bought 6 tickets $8 and 20-6=14 tickets $5.
Check:6*8+14*5=118 => 48+70=118 => 118=118.
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